A sealed flexible container holds 4.0 L of helium gas at 200. K and 1.0 atm. The container is warmed until the gas temperature reaches 400. K, while the pressure remains at 1.0 atm. What is the new volume of the gas?
A2.0 L
B4.0 L
C8.0 L
D16 L
Explanation
📌 Charles's Law (constant pressure): V₁/T₁ = V₂/T₂. Rearranging: V₂ = V₁ × (T₂/T₁) = 4.0 L × (400 K / 200 K) = 8.0 L. Doubling the absolute temperature (in Kelvin) doubles the volume at constant pressure. Always use Kelvin — converting from °C would give wildly wrong answers.
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