A student measures out 88.0 g of carbon dioxide (CO₂) for a stoichiometry experiment. How many moles of CO₂ does the sample contain? (Molar mass of CO₂ = 44.0 g/mol)
A0.500 mol
B1.00 mol
C2.00 mol
D3,872 mol
Explanation
📌 Moles = mass ÷ molar mass = 88.0 g ÷ 44.0 g/mol = 2.00 mol. The mole bridge: grams ↔ moles ↔ particles. To go from grams to moles, ALWAYS divide by molar mass. Multiplying (the common error in distractor D) gives an unreasonable answer.
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